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Infrared Spectroscopy

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ANSWER

D. The peak at 1700 indicates the presence of a carbonyl group. The bands from 3000-2800 indicate C-H alkane stretches. Finally, the bands from 1300-1000 correlate with an ester group. This narrows down the answer to D: methyl propanoate. IR and NMR are guaranteed to be problems seen in the organic chemistry section of the OAT. Either one, the other, both or even combined, with both being given and used to determine the possible compound.